Solution Found!
Sodium reacts with chlorine gas according to the reaction:2 Na(s) + Cl2(g) ? 2
Chapter 11, Problem 94P(choose chapter or problem)
Sodium reacts with chlorine gas according to the reaction:
\(2\ \mathrm{Na}(\mathrm{s})+\mathrm{Cl}_{2}(g) \rightarrow 2\ \mathrm{NaCl}(\mathrm{s})\)
What volume of \({C l}_{2}\) gas, measured at 687 torr and \(35^{\circ} \mathrm{C}\), is required to form 28 g of NaCl?
Equation Transcription:
Text Transcription:
2 Na(s)+Cl_2 (g) right arrow 2 NaCl(s)
35 degrees C
Questions & Answers
QUESTION:
Sodium reacts with chlorine gas according to the reaction:
\(2\ \mathrm{Na}(\mathrm{s})+\mathrm{Cl}_{2}(g) \rightarrow 2\ \mathrm{NaCl}(\mathrm{s})\)
What volume of \({C l}_{2}\) gas, measured at 687 torr and \(35^{\circ} \mathrm{C}\), is required to form 28 g of NaCl?
Equation Transcription:
Text Transcription:
2 Na(s)+Cl_2 (g) right arrow 2 NaCl(s)
35 degrees C
ANSWER:
Problem 94P
Sodium reacts with chlorine gas according to the reaction:
What volume of Cl2 gas, measured at 687 torr and 35 °C, is required to form 28 g of NaCl?
Step by Step Solution
Step 1 of 2
The given reaction is as follows.
From the above reaction , one mole of sodium produces 2 moles of sodium chloride.
Let’s calculate the number of moles of chlorine gas required to react with 28 g of NaCl.
Therefore, 0.24 moles of chlorine gas are required to form 28 g of NaCl.