A dioxin-contaminated water source contains 0.085% dioxin

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 54P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 54P

A dioxin-contaminated water source contains 0.085% dioxin by mass. How much dioxin is present in 2.5 L of this water? (Assume that the density of the solution is 1.01 g/mL.)

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to calculate the mass of dioxin present in 2.5 L of a dioxin- contaminated water solution containing 0.085 % dioxin by mass.

Step1:

The mass percentage of a component of a solution is defined as:

 Mass of the component in the solution

 Mass % of a component = ----------------------------------------------------- × 100         ---(1)

                                        Total mass of the solution

Step2:

Again, density may be defined as mass per unit volume.

Thus,

                                d = m / v

Here, density of the solution = 1.01 g/mL

Volume of the solution = 2.5 L = 2.5 x 1000 mL = 2500 mL        [1 L = 1000 mL]

Therefore, mass of the solution = density x volume

                                 ...

Step 2 of 3

Chapter 13, Problem 54P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

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