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# Calculate the molarity of each solution.(a) 33.2 g of KCl ISBN: 9780321910295 34

## Solution for problem 62P Chapter 13

Introductory Chemistry | 5th Edition

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Problem 62P

Calculate the molarity of each solution.

(a) 33.2 g of KCl in 0.895 L of solution

(b) 61.3 g of C2H6O in 3.4 L of solution

(c) 38.2 mg of KI in 112 mL of solution

Step-by-Step Solution:

Solution 62P :

Step 1:

Here, we have to calculate the molarity of each solution :

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

Molarity = (a) 33.2 g of KCl in 0.895 L of solution :

Given:

Amount of solute -KCl = 33.2 g

Volume of solution = 0.895 L

We have the amount of solute in g, let’s calculate the number of moles first :

Number of moles (n) = Molar mass of KCl = 74.55 g/mol.

Therefore, n = = 0.445 moles.

Now, let’s calculate the molarity :

Molarity = Molarity = 0.497 mol/L

Step 2:

(b) 61.3 g of C2H6O in 3.4 L of solution :

Given :

Amount of solute -C2H6O = 61.3 g

Volume of solution = 3.4 L

We have the amount of solute in g, let’s calculate the number of moles first :

Number of moles (n) = Molar mass of C2H6O = 46.06 g/mol.

Therefore, n = = 1.330 moles.

Now, let’s calculate the molarity :

Molarity = Molarity = 0.391 mol/L

Step 3 of 3

##### ISBN: 9780321910295

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