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Solved: A 355-mL can of soda pop contains 41 g of sucrose (C12H22O11). What is the
Chapter 13, Problem 64P(choose chapter or problem)
QUESTION:
A 355-mL can of soda pop contains 41 g of sucrose \(\mathrm {(C_{12}H_{22}O_{11})}\). What is the molarity of the solution with respect to sucrose?
Questions & Answers
QUESTION:
A 355-mL can of soda pop contains 41 g of sucrose \(\mathrm {(C_{12}H_{22}O_{11})}\). What is the molarity of the solution with respect to sucrose?
ANSWER:Step 1 of 3
Given:
Amount of solute - sucrose = 41 g
Amount of solvent - soda = 355-mL
Molarity of the solution with respect to sucrose= ?
Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.