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A 355-mL can of soda pop contains 41 g of sucrose

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 64P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 64P

A 355-mL can of soda pop contains 41 g of sucrose (C12H22O11). What is the molarity of the solution with respect to sucrose?

Step-by-Step Solution:

Solution  64P :

Step 1:

Given :

Amount of solute - sucrose (C12H22O11) = 41 g

Amount of solvent -soda  = 355-mL

Molarity of the solution with respect to sucrose= ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

                Molarity =

Amount of solvent is given in mL, let’s convert to L :

                1 L = 1000 mL

Therefore, 355 mL in L will be :

                   

                = 0.355 L

We have the amount of solute in g, let’s calculate the number of moles first :

        Number of moles (n) =

Molar mass of C12H22O11 = 342.29 g/mol.

Therefore, n =

                = 0.119 moles.

Step 2 of 2

Chapter 13, Problem 64P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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