Problem 64P

A 355-mL can of soda pop contains 41 g of sucrose (C12H22O11). What is the molarity of the solution with respect to sucrose?

Solution 64P :

Step 1:

Given :

Amount of solute - sucrose (C12H22O11) = 41 g

Amount of solvent -soda = 355-mL

Molarity of the solution with respect to sucrose= ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

Molarity =

Amount of solvent is given in mL, let’s convert to L :

1 L = 1000 mL

Therefore, 355 mL in L will be :

= 0.355 L

We have the amount of solute in g, let’s calculate the number of moles first :

Number of moles (n) =

Molar mass of C12H22O11 = 342.29 g/mol.

Therefore, n =

= 0.119 moles.