Describe how you would make 2.5 L of a 0.100 M KCl solution from a 5.5 M stock KCl solution.

Given:

Molarity of KCl (M2) = 0.1M

Volume (V2) = 2.5 L

Molarity of KCl stock solution (M1) = 5.5 M

We will have to calculate the volume (V1) = ?

It is known that the relation between molarity and volume is,

M1V1 = M2V2

Where M1 and V1 are the molarity and volume of the initial concentration of solution and M2, V2 are the molarity and volume of final dilute solution.

Now substitute the values of M1, M2 and V2 , we can get the value of V1

M1V1 = M2V2

5.5 V1 =...