Solved: Using the following data, determine the kilojoules

Chapter 2, Problem 39QP

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QUESTION:

Using the following data, determine the kilojoules for each food burned in a calorimeter:a. one stalk of celery that heats 505 g of water from 25.2 °C to 35.7 °Cb. a waffle that heats 4980 g of water from 20.6 °C to 62.4 °C

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QUESTION:

Using the following data, determine the kilojoules for each food burned in a calorimeter:a. one stalk of celery that heats 505 g of water from 25.2 °C to 35.7 °Cb. a waffle that heats 4980 g of water from 20.6 °C to 62.4 °C

ANSWER:

Solution 39QPStep 1 of 2:The goal of the problem is to determine the energy in kilojoules for each food burned in a calorimeter:We know, the formula to calculate specific heat: Specific heat = This can be rewritten to calculate heat energy as: Heat = mass Tspecific heata. Given:Mass of water = 505 g.Initial temperature (Ti ) = 25.5 °CFinal temperature (Tf ) = 35.7 °CFirst, let’s calculate T: T = Final temperature (Tf) - Initial temperature (Ti ) = 35.7 °C - 25.5 °C = 10.2 °CNow, let’s calculate the heat energy:Specific heat of water = 4.184 J/g °CTherefore, the heat energy will be: = 505 g 10.2 °C 4.184 J/g °C = 2.15104 JNow, let’s convert the energy in J to kJ. 1 kJ = 1000 JSo, the conversion factor is Therefore, the energy in kilojoules will be: = 2.15104 J = 21.55 kJ.Hence, the energy in kilojoules required for one stalk of celery that heats 505 g of water from 25.2 °C to 35.7 °C is 21.55 kJ.________________

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