Solution Found!
Determine what is wrong with the Ksp expression for Ba(OH)2 and correct it
Chapter 15, Problem 80P(choose chapter or problem)
Determine what is wrong with the \(\mathrm{K}_{s p}\) expression for \(\mathrm{Ba}(\mathrm{OH})_{2}\) and correct it.
\(K_{s p}=\frac{\left[\mathrm{Ba}(\mathrm{OH})_{2}\right]}{\left[\mathrm{Ba}^{2+}\right]\left[\mathrm{OH}^{-}\right]^{2}}\)
Equation Transcription:
Text Transcription:
K_sp
Ba(OH)_2
K_{s p}=\frac{\left[\mathrm{Ba}(\mathrm{OH})_{2}\right]}{\left[\mathrm{Ba}^{2+}\right]\left[\mathrm{OH}^{-}\right]^{2}}
Questions & Answers
QUESTION:
Determine what is wrong with the \(\mathrm{K}_{s p}\) expression for \(\mathrm{Ba}(\mathrm{OH})_{2}\) and correct it.
\(K_{s p}=\frac{\left[\mathrm{Ba}(\mathrm{OH})_{2}\right]}{\left[\mathrm{Ba}^{2+}\right]\left[\mathrm{OH}^{-}\right]^{2}}\)
Equation Transcription:
Text Transcription:
K_sp
Ba(OH)_2
K_{s p}=\frac{\left[\mathrm{Ba}(\mathrm{OH})_{2}\right]}{\left[\mathrm{Ba}^{2+}\right]\left[\mathrm{OH}^{-}\right]^{2}}
ANSWER:
Solution 80P :
Step 1:
Here, we have to determine what is wrong with the Ksp expression for Ba(OH)2 and correct it.
Ksp =
Ksp is the solubility product constant. It is the equilibrium constant of a solid substance that is dissolved in aqueous solution. It represents the level at which a solute dissolves in solution. It changes with the temperature. Ksp is the mathematical product of the concentrations of the ion dissolved raised to the power of their stoichiometric coefficients.
For the reaction :
aA(s) ⇋ cC(aq) + dD(aq)
The formula of Ksp is :
Ksp =