Solution Found!
Consider the reaction. A 3.67-L flask containing an equilibrium reaction mixture has
Chapter 15, Problem 93P(choose chapter or problem)
Consider the reaction.
\(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g) K_{\text {eq }}=6.17 \times 10^{-2} \text { at } 25^{\circ} \mathrm{C}\)
A \(3.67-\mathrm{L}\) flask containing an equilibrium reaction mixture has \(\left[\mathrm{H}_{2}\right]=0.104 \mathrm{M}\) and \(\left[\mathrm{I}_{2}\right]=0.0202 \mathrm{M}\). What mass of \(\mathrm{HI}\) in grams is in the equilibrium mixture?
Equation Transcription:
Text Transcription:
mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g) K_{\text {eq }}=6.17 \times 10^{-2} \text { at } 25^{\circ} \mathrm{C}
3.67-L
H_2=0.104M
I_2=0.0202M
HI
Questions & Answers
QUESTION:
Consider the reaction.
\(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g) K_{\text {eq }}=6.17 \times 10^{-2} \text { at } 25^{\circ} \mathrm{C}\)
A \(3.67-\mathrm{L}\) flask containing an equilibrium reaction mixture has \(\left[\mathrm{H}_{2}\right]=0.104 \mathrm{M}\) and \(\left[\mathrm{I}_{2}\right]=0.0202 \mathrm{M}\). What mass of \(\mathrm{HI}\) in grams is in the equilibrium mixture?
Equation Transcription:
Text Transcription:
mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g) K_{\text {eq }}=6.17 \times 10^{-2} \text { at } 25^{\circ} \mathrm{C}
3.67-L
H_2=0.104M
I_2=0.0202M
HI
ANSWER:
Step 1 of 4
The equilibrium equation is as follows;
Let’s write the equilibrium expression for the equilibrium reaction.
