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Chemistry / Introductory Chemistry 5 / Chapter 19 / Problem 90P

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

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Solved: A solution is made by dissolving 28.65 mg of a protein in water and diluting to

Chapter 19, Problem 90P

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QUESTION:

Problem 90P

A solution is made by dissolving 28.65 mg of a protein in water and diluting to a total volume of 25.0 mL. The osmotic pressure of the solution is 4.55 torr at 25°C. What is the molar mass of the protein? (The osmotic pressure of a solution is given by the equation: Osmotic Pressure = M × R × T, where M is the molarity of the solution, R is the gas constant, and T is temperature in K.)

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QUESTION:

Problem 90P

A solution is made by dissolving 28.65 mg of a protein in water and diluting to a total volume of 25.0 mL. The osmotic pressure of the solution is 4.55 torr at 25°C. What is the molar mass of the protein? (The osmotic pressure of a solution is given by the equation: Osmotic Pressure = M × R × T, where M is the molarity of the solution, R is the gas constant, and T is temperature in K.)

ANSWER:

Solution:

Here we have to calculate the molar mass of protein.

Given:

Step 1

The given mass of protein (w)= 28.65 mg = 0.02865g

Volume(v) = 25.0 mL = 0.025L

Osmotic pressure(p) = 4.55torr = 4.55/760 = 0.00598 atm

Temperature (T)= 25oC = 298 k (25+273)

Osmotic pressure = M $\times{}$ R $\times{}$ T

Where, M = molarity, R = gas constant, T = temperature in K

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