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Solved: tert -Butyl chloride undergoes solvolysis in both
Chapter 9, Problem 52P(choose chapter or problem)
tert-Butyl chloride undergoes solvolysis in both acetic acid and formic acid. Solvolysis occurs \(5000\) times faster in one of these two solvents than in the other. In which solvent is solvolysis faster? Explain your answer. (Hint: See \(\text{Table} \ 9.5\))
Equation Transcription:
5000
Table 9.5
Text Transcription:
5000
Table 9.5
Questions & Answers
QUESTION:
tert-Butyl chloride undergoes solvolysis in both acetic acid and formic acid. Solvolysis occurs \(5000\) times faster in one of these two solvents than in the other. In which solvent is solvolysis faster? Explain your answer. (Hint: See \(\text{Table} \ 9.5\))
Equation Transcription:
5000
Table 9.5
Text Transcription:
5000
Table 9.5
ANSWER:Solution 52P
Step 1 of 2
The reaction in which the nucleophile and the solvent are the same is called as Solvolysis.
One of the factors that influence the rate of the reaction is Solvent affects.
The reactant is tert-butyl chloride and forms a tertiary carbocation on reaction with a nucleophile.
The reaction is as follows:
The formation of the carbocation is the slow step and is the rate-determining step.
The reactant in the rate determining step is not charged. Increasing the polarity of the solvent increases the rate of the reaction.