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The existence of the NIH shift was established by

Chapter 11, Problem 32P

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QUESTION:

The existence of the \(\mathrm{NIH}\) shift was established by determining the major product obtained from

rearrangement of the following arene oxide, in which a hydrogen has been replaced by a deuterium.

a. What would be the major product if the \(\mathrm{NIH}\) shift occurs? (Hint: A \(\mathrm{C} ━ \mathrm{H}\) bond is easier to break than a \(\mathrm{C} ━ \mathrm{D}\) bond.)

b. What would be the major product if the carbocation forms phenol by losing a proton, rather

than by going through the \(\mathrm{NIH}\) shift?

Equation Transcription:

NIH

C ━ H

C ━ D

Text Transcription:

NIH

C ━ H

C ━ D

Questions & Answers

QUESTION:

The existence of the \(\mathrm{NIH}\) shift was established by determining the major product obtained from

rearrangement of the following arene oxide, in which a hydrogen has been replaced by a deuterium.

a. What would be the major product if the \(\mathrm{NIH}\) shift occurs? (Hint: A \(\mathrm{C} ━ \mathrm{H}\) bond is easier to break than a \(\mathrm{C} ━ \mathrm{D}\) bond.)

b. What would be the major product if the carbocation forms phenol by losing a proton, rather

than by going through the \(\mathrm{NIH}\) shift?

Equation Transcription:

NIH

C ━ H

C ━ D

Text Transcription:

NIH

C ━ H

C ━ D

ANSWER:

Solution 32P

(a)

Protonation of the epoxide gives an oxonium ion and then bond between carbon and oxygen breaks to form a carbocation. Then 1,2-hydride shift occurs and next the base abstracts the proton and forms the major product. Thus, the reaction is shown as follows:

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