A sodium nitrate solution is 12.5% NaNO3 by mass and has a

Chapter 12, Problem 6SAQ

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QUESTION:

A sodium nitrate solution is 12.5% \(\mathrm{NaNO}_{3}\) by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.

a) 1.44 M                

b) 12.8 M                 

c) 6.67 M                

d) 1.50 M

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QUESTION:

A sodium nitrate solution is 12.5% \(\mathrm{NaNO}_{3}\) by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.

a) 1.44 M                

b) 12.8 M                 

c) 6.67 M                

d) 1.50 M

ANSWER:

Problem 6SAQ

A sodium nitrate solution is 12.5% NaNO3 by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.

a) 1.44 M

b) 12.8 M

c) 6.67 M

d) 1.50 M

        

                                                              Step by Step Solution

Step 1 of 2

From the given,

Mass percentage NaNO_{3} of  = 12.5 %

Density of NaNO_{3} = 1.02 g/ml

Molar mass NaNO_{3} of  = 1.02 g/ml

Let’s convert the given mass into moles.

                                        12.5g\,NaNO_{3}\times \frac{1\,mol}{85\,g\,NaNO_{3}} = 0.147 mol

Hence, the number of moles of solution is 0.147 mol.

Let’s calculate the density milliliter into liters.

                                                  100g\times \frac{1ml}{1.02 g}\times \frac{10^{-3}L}{mL} = 0.098 L

Hence, the volume of the solution is 0.098 L.

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