A diverging lens is placed next to a converging lens of

Chapter 32, Problem 65P

(choose chapter or problem)

(II) A diverging lens is placed next to a converging lens of focal length \(f_{\mathrm{C}}\), as in Fig. 23–42. If \(f_{\mathrm{T}}\) represents the focal length of the combination, show that the focal length of the diverging lens, \(f_{\mathrm{D}}\), is given by

                               \(\frac{1}{f_{\mathrm{D}}}=\frac{1}{f_{\mathrm{T}}}-\frac{1}{f_{\mathrm{C}}}\)

Equation Transcription:

Text Transcription:

f_C

f_T

f_D

{1 over f_D} ={1 over f_T}={1 over f_C}