Solved: (II) The nuclide decays by emitting an electron

Chapter 30, Problem 32P

(choose chapter or problem)

$\text { (II) }$ The nuclide ${ }_{15}^{32} P$ decays by emitting an electron whose maximum kinetic energy can be $\text { 1.71MeV }$.

( $a$ ) What is the daughter nucleus?

(b) Calculate the daughter's atomic mass (in u).

Equation Transcription:

$(II)$

${\ }_{15}^{32}P$

$1.71MeV$

Text Transcription:

(II)

15 ^ 32P

1.71MeV

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