Convert each measurement to atm.(a) 1277 mm Hg(b) 2.38 ×

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 23Q Chapter 11

Introductory Chemistry | 5th Edition

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Problem 23Q

PROBLEM 23P

Convert each measurement to atm.

(a) 1277 mm Hg

(b) 2.38 × 105 Pa

(d) 455 torr

Step-by-Step Solution:

Solution 23P

Step 1:

(a) 1277 mm Hg

Pressure of gas = 1277 mm Hg

It is known that 1 atm = 760 mm Hg

Conversion factor used = 1 atm/ 760 mm Hg

We have multiply the given pressure of the gas in mmHg with the conversion factor, to calculate the pressure in the atmosphere.

Hence, 1277 mm Hg $\times{}$ $\frac{1\ atm}{760mm\ Hg}$ = 1.680 atm

Therefore the pressure of the gas in atmosphere is 1.680atm

Step 2:

(b) 2.38 × 105 Pa

Pressure of gas = 2.38 × 105 Pa

We will use the conversion factor, to convert the pressure in pa to atm.

pressure in atm = (pressure on Pa) $\times{}$ (1 atm/1.01325 x 105 Pa)

= (2.38 × 105 Pa) $\times{}$ (1 atm/1.01325 $\times{}$ 105 Pa)

=2.38 × 105 /1.01325 $\times{}$ 105 atm ((the Pa unit cancels out)

=2.3488 atm

Therefore the pressure of the gas in atmosphere is 2.3488 atm

Step 3 of 4

Chapter 11, Problem 23Q is Solved

Step 4 of 4

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

This full solution covers the following key subjects: atm, convert, measurement, PSI, torr. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 23Q from chapter: 11 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “Convert each measurement to atm.(a) 1277 mm Hg(b) 2.38 × 105 Pa(c) 127 psi(d) 455 torr” is broken down into a number of easy to follow steps, and 16 words. Since the solution to 23Q from 11 chapter was answered, more than 925 students have viewed the full step-by-step answer.