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Solved: Auto Fatalities The table below lists auto

Elementary Statistics | 12th Edition | ISBN: 9780321836960 | Authors: Mario F. Triola ISBN: 9780321836960 18

Solution for problem 1 RE Chapter 11.3

Elementary Statistics | 12th Edition

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Elementary Statistics | 12th Edition | ISBN: 9780321836960 | Authors: Mario F. Triola

Elementary Statistics | 12th Edition

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Problem 1 RE

Problem  1RE

Auto Fatalities The table below lists auto fatalities by day of the week for a recent year (based on data from the Federal Highway Administration). Minitab results are also shown. Use a 0.01 significance level to test the claim that auto fatalities occur on the different days of the week with the same frequency. Can you provide an explanation for the results?

Day

Mon

Tues

Wed

Thurs

Fri

Sat

Sun

Frequency

3797

3615

3724

4004

4867

5786

5004

Step-by-Step Solution:

Answer:

Step 1 of 2</p>

The expected values for each category, Ei , could be determined. With these observed and expected numbers of cases, the hypotheses can be written as

H0 : the claim that auto fatalities occur on the different days of the week with the same frequency

H1 : the claim that auto fatalities occur on the different days of the week with the different frequency.

Use a 0.05 significance level

SL. No.

O

p = 1/7

E = np

(O - E )2

(O - E)2/E

1

3797

0.142857

4399.571

363092.3

82.52902

2

3615

0.142857

4399.571

615552.3

139.9119

3

3724

0.142857

4399.571

456396.8

103.7366

4

4004

0.142857

4399.571

156476.8

35.56636

5

4867

0.142857

4399.571

218489.5

49.66153

6

5786

0.142857

4399.571

1922184

436.9026

7

5004

0.142857

4399.571

365333.9

83.03852

Sum

30797

1

30797

4097526

931.3466

The first step in conducting the significance test is to compute the expected frequency for each outcome given that the null hypothesis is true. For example, the expected frequency of a "1" is 7 since the probability of a "1" coming up is 1/7 and there were a total of 30797.

Expected frequency (E) = np

                                       = 30797(1/7)

                                       = 4399.571

The calculation continues as follows. Letting E be the expected frequency of an outcome and O be the observed frequency of that outcome.

Step 2 of 2

Chapter 11.3, Problem 1 RE is Solved
Textbook: Elementary Statistics
Edition: 12
Author: Mario F. Triola
ISBN: 9780321836960

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Solved: Auto Fatalities The table below lists auto

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