Solution Found!
Answer: The graph in Fig. E2.31 shows the velocity of a
Chapter 2, Problem 31E(choose chapter or problem)
The graph in Fig. E2.31 shows the velocity of a motorcycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at t = 3 s, at t = 7 s, and at t = 11 s. (b) How far does the officer go in the first 5 s? The first 9 s? The first 13 s?
Questions & Answers
QUESTION:
The graph in Fig. E2.31 shows the velocity of a motorcycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at t = 3 s, at t = 7 s, and at t = 11 s. (b) How far does the officer go in the first 5 s? The first 9 s? The first 13 s?
ANSWER:
Step 1 of 3
According to the kinematic equation, the acceleration is given by
\(a=\frac{\Delta v}{\Delta t} \quad \Rightarrow(1)\)
The change in velocity is given by
\(\Delta v=v_{f}-v_{i} \quad \Rightarrow(2)\)
AAnd The change in time is given by
\(\Delta t=t_{f}-t_{i} \quad \Rightarrow(3)\)
Where :
\(v_{i}\) is the initial velocity of the interval.
\(v_{f}\) is the final velocity of the interval.
\(t_{i}\) is the beginning of the interval.
\(t_{f}\) is the end of the interval.