Solution Found!
Solved: Determined to test the law of gravity for himself,
Chapter 2, Problem 92P(choose chapter or problem)
Problem 92P
Determined to test the law of gravity for himself, a student walks off a skyscraper 180 m high, stopwatch in hand. and starts his free fall (zero initial velocity). Five seconds later, Superman arrives at the scene and dives off the roof to save the student. Superman leaves the roof with an initial speed v0 that he produces by pushing himself downward from the edge or the roof with his legs of steel. He then falls with the same acceleration as any freely falling body. (a) What must the value of υ0 be so that Superman catches the student just before they reach the ground? (b) On the same graph sketch tbe positions of the student and of Superman as functions of time. Take Superman’s initial speed to have the value calculated in part (a). (c) If the height of the skyscraper is less than some minimum value, even Superman can’t reach the student before be hits the ground. What is this minimum height?
Questions & Answers
QUESTION:
Problem 92P
Determined to test the law of gravity for himself, a student walks off a skyscraper 180 m high, stopwatch in hand. and starts his free fall (zero initial velocity). Five seconds later, Superman arrives at the scene and dives off the roof to save the student. Superman leaves the roof with an initial speed v0 that he produces by pushing himself downward from the edge or the roof with his legs of steel. He then falls with the same acceleration as any freely falling body. (a) What must the value of υ0 be so that Superman catches the student just before they reach the ground? (b) On the same graph sketch tbe positions of the student and of Superman as functions of time. Take Superman’s initial speed to have the value calculated in part (a). (c) If the height of the skyscraper is less than some minimum value, even Superman can’t reach the student before be hits the ground. What is this minimum height?
ANSWER:
Solution 92P
Step 1 of 6:
We can apply the constant acceleration equations to the motion of each person because Both objects are in fall.
Let +y be downward, so =+ 9.8 m\