Answer: A boxed 10.0-kg computer monitor is dragged by

Chapter 6, Problem 11E

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QUESTION:

A boxed 10.0-kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of \(36.9^{\circ}\) above the horizontal. If the monitor’s speed is a constant 2.10 cm/s, how much work is done on the monitor by

(a) friction,

(b) gravity, and

(c) the normal force of the conveyor belt?

Questions & Answers

QUESTION:

A boxed 10.0-kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of \(36.9^{\circ}\) above the horizontal. If the monitor’s speed is a constant 2.10 cm/s, how much work is done on the monitor by

(a) friction,

(b) gravity, and

(c) the normal force of the conveyor belt?

ANSWER:

Step 1 of 3

The force acting on the box will be, F = - mg sin

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