Solution Found!
Answer: A boxed 10.0-kg computer monitor is dragged by
Chapter 6, Problem 11E(choose chapter or problem)
A boxed 10.0-kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of \(36.9^{\circ}\) above the horizontal. If the monitor’s speed is a constant 2.10 cm/s, how much work is done on the monitor by
(a) friction,
(b) gravity, and
(c) the normal force of the conveyor belt?
Questions & Answers
QUESTION:
A boxed 10.0-kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of \(36.9^{\circ}\) above the horizontal. If the monitor’s speed is a constant 2.10 cm/s, how much work is done on the monitor by
(a) friction,
(b) gravity, and
(c) the normal force of the conveyor belt?
ANSWER:Step 1 of 3
The force acting on the box will be, F = - mg sin