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Answer: A 3.00-kg block is connected to two ideal
Chapter 7, Problem 70P(choose chapter or problem)
A \(3.00-\mathrm{kg}\) block is connected to two ideal horizontal springs having force constants
\(k_{1}=25.0 \mathrm{~N} / \mathrm{cm}\) and \(k_{2}=200 \mathrm{~N} / \mathrm{cm}\) and (Fig. P7.70). The system is initially in equilibrium on a horizontal, frictionless surface. The block is now pushed \(15.0 \mathrm{~cm}\) to the right and released from rest. (a) What is the maximum speed of the block? Where in the motion does the maximum speed occur? (b) What is the maximum compression of spring 1?
Equation Transcription:
Text Transcription:
3.00-kg
k_1=25.0 N/cm
k_2=200 N/cm
15.0 cm
Questions & Answers
QUESTION:
A \(3.00-\mathrm{kg}\) block is connected to two ideal horizontal springs having force constants
\(k_{1}=25.0 \mathrm{~N} / \mathrm{cm}\) and \(k_{2}=200 \mathrm{~N} / \mathrm{cm}\) and (Fig. P7.70). The system is initially in equilibrium on a horizontal, frictionless surface. The block is now pushed \(15.0 \mathrm{~cm}\) to the right and released from rest. (a) What is the maximum speed of the block? Where in the motion does the maximum speed occur? (b) What is the maximum compression of spring 1?
Equation Transcription:
Text Transcription:
3.00-kg
k_1=25.0 N/cm
k_2=200 N/cm
15.0 cm
ANSWER:
Solution to 70P
Step 1
Mass of the block =3kg
Distance the spring was compressed =15cm=15x102m
K1=25N/cm =25x102N/m
K2 =20N/cm =20x102N/m