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Answer: A 2.20-kg hoop 1.20 m in diameter is rolling to
Chapter 10, Problem 19E(choose chapter or problem)
Problem 19E
A 2.20-kg hoop 1.20 m in diameter is rolling to the right without slipping on a horizontal floor at a steady 3.00 rad/s. (a) How fast is its center moving? (b) What is the total kinetic energy of the hoop? (c) Find the velocity vector of each of the following points, as viewed by a person at rest on the ground: (i) the highest point on the hoop; (ii) the lowest point on the hoop; (iii) a point on the right side of the hoop, midway between the top and the bottom. (d) Find the velocity vector for each of the points in Part (c), but this time as viewed by someone moving along with the same velocity as the hoop.
Questions & Answers
QUESTION:
Problem 19E
A 2.20-kg hoop 1.20 m in diameter is rolling to the right without slipping on a horizontal floor at a steady 3.00 rad/s. (a) How fast is its center moving? (b) What is the total kinetic energy of the hoop? (c) Find the velocity vector of each of the following points, as viewed by a person at rest on the ground: (i) the highest point on the hoop; (ii) the lowest point on the hoop; (iii) a point on the right side of the hoop, midway between the top and the bottom. (d) Find the velocity vector for each of the points in Part (c), but this time as viewed by someone moving along with the same velocity as the hoop.
ANSWER:
Solution 19E
The moment of inertia of a hoop is , where M is the mass of the hoop and R is its radius. The top point of the hoop will have double the linear speed and the bottom point will have zero speed as it is momentarily at rest.
The situation can be summarized as shown in the figure below.