Solution Found!
Answer: A 350-N, uniform, 1.50-m bar is suspended
Chapter 11, Problem 9E(choose chapter or problem)
Problem 9E
A 350-N, uniform, 1.50-m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tension of 500.0 N without breaking, and cable B can support up to 400.0 N. You want to place a small weight on this bar. (a) What is the heaviest weight you can put on without breaking either cable, and (b) where should you put this weight?
Questions & Answers
QUESTION:
Problem 9E
A 350-N, uniform, 1.50-m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tension of 500.0 N without breaking, and cable B can support up to 400.0 N. You want to place a small weight on this bar. (a) What is the heaviest weight you can put on without breaking either cable, and (b) where should you put this weight?
ANSWER:Solution 9E
Step 1:
a) For equilibrium, the total force will be zero.
So, we can write, FA + FB - Fg - Fx = 0
where , FA - maximum tension of cable A
FB - maximum tension of cable B
Fg - Weight of the rod
Fx - Maximum weight which it can with stand
We are putting negative sign for Fg and Fx because it is acting downward
Therefore, FA + FB - Fg = Fx
Provided, FA = 500 N
FB = 400 N
Fg = 350 N
Therefore, maximum weight the cables can withstand, Fx = 500 N + 400 N - 350 N = 650 N