Solution Found!
A diving board 3.00 m long is supported at a
Chapter 11, Problem 34E(choose chapter or problem)
In the Challenger Deep of the Marianas Trench, the depth of seawater is \(10.9 \mathrm{~km}\) and the pressure is \(1.16 \times 10^{8}\) Pa (about \(1.15 \times 10^{3}\) atm ).
(a) If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is about \(1.0 \times 10^{5}\)Pa. Assume that ƙ for seawater is the same as the freshwater value given in Table 11.2.)
(b) What is the density of seawater at this depth? (At the surface, seawater has a density of \(1.03 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).)
Equation Transcription:
Text Transcription:
10.9 km
1.16 times 10^8
1.15 times 10^3
1.0 times 10^5
1.03 times 10^3kg/m^3
Questions & Answers
QUESTION:
In the Challenger Deep of the Marianas Trench, the depth of seawater is \(10.9 \mathrm{~km}\) and the pressure is \(1.16 \times 10^{8}\) Pa (about \(1.15 \times 10^{3}\) atm ).
(a) If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is about \(1.0 \times 10^{5}\)Pa. Assume that ƙ for seawater is the same as the freshwater value given in Table 11.2.)
(b) What is the density of seawater at this depth? (At the surface, seawater has a density of \(1.03 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).)
Equation Transcription:
Text Transcription:
10.9 km
1.16 times 10^8
1.15 times 10^3
1.0 times 10^5
1.03 times 10^3kg/m^3
ANSWER:
Solution 34E
The system of the person and diving board is at rest so the two conditions of equilibrium apply;the vector sum of all external forces acting on the body is zero;
=0 the sum of the torques due to all external forces acting on the body, with respect to any specified point, must be zero.
Step 1 of 2:
The free body diagram for the diving board is as shown in the fig below.
Take the origin of the co ordinates at the left hand end of the board.
is the force applied at the support point and
is the force at the end A that is held down.
Now,which gives
+)
= 0
1920 N