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Solved: Hooke’s Law for a Wire. A wire of length where Y
Chapter 11, Problem 88P(choose chapter or problem)
Hooke’s Law for a Wire. A wire of length \(l_{0}\) and cross-sectional area A supports a hanging weight W. (a) Show that if the wire obeys Eq. (11.7), it behaves like a spring of force constant \(A Y / L_{0}\), where Y is Young’s modulus for the material of which the wire is made. (b) What would the force constant be for a 75.0-cm length of 16-gauge (diameter = 1.291 mm) copper wire? See Table 11.1. (c) What would W have to be to stretch the wire in part (b) by 1.25 mm?
Questions & Answers
QUESTION:
Hooke’s Law for a Wire. A wire of length \(l_{0}\) and cross-sectional area A supports a hanging weight W. (a) Show that if the wire obeys Eq. (11.7), it behaves like a spring of force constant \(A Y / L_{0}\), where Y is Young’s modulus for the material of which the wire is made. (b) What would the force constant be for a 75.0-cm length of 16-gauge (diameter = 1.291 mm) copper wire? See Table 11.1. (c) What would W have to be to stretch the wire in part (b) by 1.25 mm?
ANSWER:Solution 88P
Step 1:
Introduction
In this question we have a wire, we need to find the force constant copper wire
In the second part, we need to find weight by the wire can be stretched by 1.25 mm
Data given
Length of the wire
Diameter of the wire
radius
Amount stretched
Young’s modulus