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Solved: M&Ms In we drew a histogram of the weights of M&Ms
Chapter 10, Problem 13AYU(choose chapter or problem)
In Problem 27 from Section 3.1, we drew a histogram of the weights of M&Ms and found that the distribution is symmetric. Draw a boxplot of these data. Use the boxplot and quartiles to confirm the distribution is symmetric. For convenience, the data are displayed again.
\(\begin{array}{l}
\begin{array}{lllllll}
0.87 & 0.88 & 0.82 & 0.90 & 0.90 & 0.84 & 0.84 \\
\hline 0.91 & 0.94 & 0.86 & 0.86 & 0.86 & 0.88 & 0.87 \\
\hline 0.89 & 0.91 & 0.86 & 0.87 & 0.93 & 0.88 & \\
\hline 0.83 & 0.95 & 0.87 & 0.93 & 0.91 & 0.85 & \\
\hline 0.91 & 0.91 & 0.86 & 0.89 & 0.87 & 0.84 & \\
\hline 0.88 & 0.88 & 0.89 & 0.79 & 0.82 & 0.83 & \\
\hline 0.90 & 0.88 & 0.84 & 0.93 & 0.81 & 0.90 & \\
\hline 0.88 & 0.92 & 0.85 & 0.84 & 0.84 & 0.86 & \\
\hline
\end{array}\\
\text { Source: Michael Sullivan }
\end{array}\)
Questions & Answers
QUESTION:
In Problem 27 from Section 3.1, we drew a histogram of the weights of M&Ms and found that the distribution is symmetric. Draw a boxplot of these data. Use the boxplot and quartiles to confirm the distribution is symmetric. For convenience, the data are displayed again.
\(\begin{array}{l}
\begin{array}{lllllll}
0.87 & 0.88 & 0.82 & 0.90 & 0.90 & 0.84 & 0.84 \\
\hline 0.91 & 0.94 & 0.86 & 0.86 & 0.86 & 0.88 & 0.87 \\
\hline 0.89 & 0.91 & 0.86 & 0.87 & 0.93 & 0.88 & \\
\hline 0.83 & 0.95 & 0.87 & 0.93 & 0.91 & 0.85 & \\
\hline 0.91 & 0.91 & 0.86 & 0.89 & 0.87 & 0.84 & \\
\hline 0.88 & 0.88 & 0.89 & 0.79 & 0.82 & 0.83 & \\
\hline 0.90 & 0.88 & 0.84 & 0.93 & 0.81 & 0.90 & \\
\hline 0.88 & 0.92 & 0.85 & 0.84 & 0.84 & 0.86 & \\
\hline
\end{array}\\
\text { Source: Michael Sullivan }
\end{array}\)
Step 1 of 2
\(\begin{array}{l}
\begin{array}{lllllll}
0.87 & 0.88 & 0.82 & 0.90 & 0.90 & 0.84 & 0.84 \\
\hline 0.91 & 0.94 & 0.86 & 0.86 & 0.86 & 0.88 & 0.87 \\
\hline 0.89 & 0.91 & 0.86 & 0.87 & 0.93 & 0.88 & \\
\hline 0.83 & 0.95 & 0.87 & 0.93 & 0.91 & 0.85 & \\
\hline 0.91 & 0.91 & 0.86 & 0.89 & 0.87 & 0.84 & \\
\hline 0.88 & 0.88 & 0.89 & 0.79 & 0.82 & 0.83 & \\
\hline 0.90 & 0.88 & 0.84 & 0.93 & 0.81 & 0.90 & \\
\hline 0.88 & 0.92 & 0.85 & 0.84 & 0.84 & 0.86 & \\
\hline
\end{array}\\
\text { Source: Michael Sullivan }
\end{array}\)