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Answer: A wire with mass 40.0 g is stretched so that its
Chapter 15, Problem 41E(choose chapter or problem)
Problem 41E
A wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart. The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.300 cm. (a) What is the speed of propagation of transverse waves in the wire? (b) Compute the tension in the wire. (c) Find the maximum transverse velocity and acceleration of particles in the wire.
Questions & Answers
QUESTION:
Problem 41E
A wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart. The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.300 cm. (a) What is the speed of propagation of transverse waves in the wire? (b) Compute the tension in the wire. (c) Find the maximum transverse velocity and acceleration of particles in the wire.
ANSWER:Solution to 41E
Step 1 of 4
Introduction,
The stretched wire vibrates with fundamental frequency of 60Hz, we are asked to find the wave velocity, the tension in the wire, and maximum transverse velocity and accelerations of particles in the wire,
Given,
Mass of the wire=40g = 40x10-3kg
Length of the wire =0.8m
Frequency of vibration=60Hz
Amplitude at anti node =0.3cm