Solution Found!
Answer: A nonuniform beam 4.50 m long and weighing 1.00 kN
Chapter 11, Problem 20E(choose chapter or problem)
A nonuniform beam 4.50 m long and weighing 1.00 kN makes an angle of \(25.0^{\circ}\) below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 3.00 m farther down the beam and perpendicular to it (Fig. E11.20). The center of gravity of the beam is 2.00 m down the beam from the pivot. Lighting equipment exerts a 5.00-kN downward force on the lower left end of the beam. Find the tension T in the cable and the horizontal and vertical components of the force exerted on the beam by the pivot. Start by sketching a free-body diagram of the beam.
Equation Transcription:
Text Transcription:
25deg
25deg
Questions & Answers
QUESTION:
A nonuniform beam 4.50 m long and weighing 1.00 kN makes an angle of \(25.0^{\circ}\) below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 3.00 m farther down the beam and perpendicular to it (Fig. E11.20). The center of gravity of the beam is 2.00 m down the beam from the pivot. Lighting equipment exerts a 5.00-kN downward force on the lower left end of the beam. Find the tension T in the cable and the horizontal and vertical components of the force exerted on the beam by the pivot. Start by sketching a free-body diagram of the beam.
Equation Transcription:
Text Transcription:
25deg
25deg
ANSWER:
Solution 20E