Solution Found!
Solved: In Example 42.2 the moment of inertia for CO was
Chapter 42, Problem 9E(choose chapter or problem)
In Example 42.2 the moment of inertia for CO was calculated using Eq. (42.6). (a) In CO, how far is each atom from the center of mass of the molecule? (b) Use \(I=m_{1} r_{1}^{2}+m_{2} r_{2}^{2}\) to calculate the moment of inertia of CO about an axis through the center of mass and perpendicular to the line joining the centers of the two atoms. Does your result agree with the value obtained in Example 42.2?
Questions & Answers
QUESTION:
In Example 42.2 the moment of inertia for CO was calculated using Eq. (42.6). (a) In CO, how far is each atom from the center of mass of the molecule? (b) Use \(I=m_{1} r_{1}^{2}+m_{2} r_{2}^{2}\) to calculate the moment of inertia of CO about an axis through the center of mass and perpendicular to the line joining the centers of the two atoms. Does your result agree with the value obtained in Example 42.2?
ANSWER: