×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide

You are standing on a sheet of ice that covers the

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 20E Chapter 8

University Physics | 13th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 1 273 Reviews
30
5
Problem 20E

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo: there is negligible friction between your feet and the ice. A friend throws you a 0.400 kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move afterward? (b) If the ball hits you and bounces off your chest, so afterward it is moving horizontally at 8.0 m/s in the opposite direction, what is your speed after the collision?

Step-by-Step Solution:

Solution 20E Problem (a) Step 1: Mass of the person m = 70Kg 1 Mass of the ball m = 0.402 Velocity of the person before collision v = 0 1 Velocity of the ball v = 10.0m/s 2 Step 2: If the person catches the ball, the momentum is conserved. The total momentum before collision is equal to the total momentum after collision. After collision both the person and the ball move together along the same direction with same velocity. Step 3: Therefore m v + m v = (m +m )v 1 1 2 2 1 2 f Where v is fe velocity of the ball and the person Since v =1 m v = (m +m )v 2 2 1 2 f Step 4: Applying known values m v v = 2 2 f (m 1m ) 2 0.4 10 vf (70+0.4) v = 0.0568 m/s f Velocity of the person and the ball after the catch is 0.0568 m/s Problem (b) Step 1: The ball hits the person and moves with 8.0m/s (v ) in the opposite2irection. Therefore v = -20m/s So the ball and the person moves in opposite direction. Step 2: From conservation of momentum m2 2 m v1 1 v 2 2 Initial momentum of the person is zero. Where v is1 e velocity of the person after collision u2 s the initial velocity of the ball (10m/s)

Step 3 of 3

Chapter 8, Problem 20E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

This full solution covers the following key subjects: ball, speed, afterward, ice, horizontally. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 20E from 8 chapter was answered, more than 372 students have viewed the full step-by-step answer. The answer to “You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo: there is negligible friction between your feet and the ice. A friend throws you a 0.400 kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move afterward? (b) If the ball hits you and bounces off your chest, so afterward it is moving horizontally at 8.0 m/s in the opposite direction, what is your speed after the collision?” is broken down into a number of easy to follow steps, and 94 words. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 20E from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

You are standing on a sheet of ice that covers the

×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide
×
Reset your password