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An airplane propeller is rotating at 1900 rpm (rev/min).

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 2E Chapter 9

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 2E

An airplane propeller is rotating at 1900 rpm (rev/min). (a) Compute the propeller’s angular velocity in rad/s. (b) How many seconds does it take for the propeller to turn through 35o?

Step-by-Step Solution:

Solution 2E Step 1 of 6: An airplane propeller is rotating at 1900 rpm (rev/min). (a) Compute the propeller’s angular velocity in rad/s. In the given problem, the angular speed is given in revolution per minute, we need to convert the given angular speed to radian per sec. One complete revolution is equal to 2 rad, That is 1 rev= 2 rad Similarly 1min has 60sec, 1 min = 60 sec Step 2 of 6: To convert angular speed from rev/min to rad/sec Given angular speed, =1900 rev/min Using 1 rev= 2 rad and 1 min = 60 sec rev 2rad 1 min = 1900( min)( 1 rev)(60 sec Step 3 of 6: = 1900( 2rad) 60 sec = 1900( 60 sec =63.33 rad/sec =199 rad/sec Therefore, the airplane propeller angular speed is 63.33 rad/sec or 199 rad/sec.

Step 4 of 6

Chapter 9, Problem 2E is Solved
Step 5 of 6

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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