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Calculating Percent Error: Insights into Experiment Accuracy & Refinem
Chapter 1, Problem 1.77(choose chapter or problem)
Percent error is often expressed as the absolute value of the difference between the true value and the experimental value, divided by the true value:
\(\text { percent error }=\frac{\mid \text { true value }-\text { experimental value } \mid}{\mid \text { true value } \mid} \times 100 \%\)
The vertical lines indicate absolute value. Calculate the percent error for the following measurements:
(a) The density of alcohol (ethanol) is found to be 0.802 g/mL. (True value: 0.798 g/mL.)
(b) The mass of gold in an earring is analyzed to be 0.837 g. (True value: 0.864 g.)
Questions & Answers
QUESTION:
Percent error is often expressed as the absolute value of the difference between the true value and the experimental value, divided by the true value:
\(\text { percent error }=\frac{\mid \text { true value }-\text { experimental value } \mid}{\mid \text { true value } \mid} \times 100 \%\)
The vertical lines indicate absolute value. Calculate the percent error for the following measurements:
(a) The density of alcohol (ethanol) is found to be 0.802 g/mL. (True value: 0.798 g/mL.)
(b) The mass of gold in an earring is analyzed to be 0.837 g. (True value: 0.864 g.)
ANSWER:Step 1 of 3
The percent error can be calculated as follows,
\(\text { Percent error }=\frac{\mid \text { true value }- \text { experimental value } \mid}{\mid \text { true value } \mid} \times 100 \%\)
(a) Given:
The density of alcohol = 0.802 g/mL
True value = 0.798 g/mL
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Calculating Percent Error: Insights into Experiment Accuracy & Refinem
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Discover the importance of calculating percent error to assess the precision of experiments. Through real-world examples like measuring alcohol's density and the mass of gold, learn how this value offers insights into measurement accuracy and ways to refine methods.