Answer: A sheet of aluminum (Al) foil has a total area of

Step 1 of 2

Here we have to calculate the thickness of the foil in millimeter

Given:

Area of aluminum foil = \(1.000 \ \mathrm{ft}^{2}\)

Mass = 3.636 gm

Density of Al = \(2.699 \mathrm{~g} / \mathrm{cm}^{3}\)

The thickness can be calculated as, thickness \(=\frac{\text { Volume }}{\text { area }}\)

So in order to calculate thickness we will have to find out volume i.e volume = mass/density

\(\text { Volume }=\frac{3.636 \mathrm{gm}}{2.699 \mathrm{~g} / \mathrm{cm}^{3}}=1.3472 \mathrm{~cm}^{3}\)