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Chemistry / Chemistry 11 / Chapter 6 / Problem 100P

Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang

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Solved: A quantity of 0.020 mole of a gas initially at

Chapter 6, Problem 100P

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QUESTION:

A quantity of 0.020 mole of a gas initially at 0.050 L and \(20^{\circ} \mathrm{C}\) undergoes a constant-temperature expansion until its volume is 0.50 L. Calculate the work done (in joules) by the gas if it expands (a) against a vacuum and (b) against a constant pressure of 0.20 atm. (c) If the gas in (b) is allowed to expand unchecked until its pressure is equal to the external pressure, what would its final volume be before it stopped expanding, and what would be the work done?

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QUESTION:

A quantity of 0.020 mole of a gas initially at 0.050 L and \(20^{\circ} \mathrm{C}\) undergoes a constant-temperature expansion until its volume is 0.50 L. Calculate the work done (in joules) by the gas if it expands (a) against a vacuum and (b) against a constant pressure of 0.20 atm. (c) If the gas in (b) is allowed to expand unchecked until its pressure is equal to the external pressure, what would its final volume be before it stopped expanding, and what would be the work done?

ANSWER:

Step 1 of 5

(a) Here we have to calculate the work done (in joules) by the gas if it expands against vacuum.

Given:

Mole of gas = 0.020 mole

Initial volume () = 0.050 L

Final volume () = 0.50 L

The change in volume $\Delta{}V\ =\ {V}_{2}-{V}_{1}$ = (0.50 - 0.050) L = 0.45 L

Temperature = 20 °C + 273 = 293 K

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