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How many molecules of Ethane (C2H6) are present in 0.334 g of Ethane?

Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang ISBN: 9780073402680 118

Solution for problem 26P Chapter 3

Chemistry | 11th Edition

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Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang

Chemistry | 11th Edition

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Problem 26P

How many molecules of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\) are present in 0.334 g of \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\)?

Step-by-Step Solution:

Step 1 of 2

Here, we are going to calculate the number of molecules of ethane in 0.334 g.

We know that,

The molar mass of ethane = 2(12.01 g) + 6(1.008 g) = 30.07 g/mol

1.0 mol of ethane =  molecules of ethane

1.0 mol of ethane contains = 30.07 g

Step 2 of 2

Chapter 3, Problem 26P is Solved
Textbook: Chemistry
Edition: 11
Author: Raymond Chang
ISBN: 9780073402680

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