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Solved: From the following data, calculate the enthalpy
Chapter 6, Problem 62P(choose chapter or problem)
From the following data,
\(\mathrm{C}(\text { graphite })+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(g)\)
\(\Delta H_{r x n}^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(H_{2}(g)+\frac{1}{2} O_{2}(g) \rightarrow H_{2} O(l)\)
\(\Delta H_{r x n}^{\circ}=-285.8\ \mathrm{kJ} / \mathrm{mol}\)
\(2 \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})+7 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
\(\Delta H_{r x n}^{\circ}=-3119.6\ \mathrm{kJ} / \mathrm{mol}\)
calculate the enthalpy change for the reaction
\(2 \mathrm{C}(\text { graphite })+3 \mathrm{H}_{2}(\mathrm{g}) \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})\)
Questions & Answers
QUESTION:
From the following data,
\(\mathrm{C}(\text { graphite })+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(g)\)
\(\Delta H_{r x n}^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(H_{2}(g)+\frac{1}{2} O_{2}(g) \rightarrow H_{2} O(l)\)
\(\Delta H_{r x n}^{\circ}=-285.8\ \mathrm{kJ} / \mathrm{mol}\)
\(2 \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})+7 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
\(\Delta H_{r x n}^{\circ}=-3119.6\ \mathrm{kJ} / \mathrm{mol}\)
calculate the enthalpy change for the reaction
\(2 \mathrm{C}(\text { graphite })+3 \mathrm{H}_{2}(\mathrm{g}) \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})\)
ANSWER:Step 1 of 3
Here, we are going to calculate the enthalpy change for the reaction.