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Solved: The standard enthalpy change ?H° for the thermal
Chapter 6, Problem 75P(choose chapter or problem)
The standard enthalpy change \(\Delta H^{\circ}\) for the thermal decomposition of silver nitrate according to the following equation is +78.67 kJ:
\(\mathrm{AgNO}_{3}(s) \rightarrow A g N \mathrm{NO}_{2}(s)+\frac{1}{2} \mathrm{O}_{2}(g)\)
The standard enthalpy of formation of \(\mathrm{AgNO}_{3}(\mathrm{s})\) is -123.02 kJ/mol. Calculate the standard enthalpy of formation of \(\mathrm{AgNO}_{2}(s)\).
Questions & Answers
QUESTION:
The standard enthalpy change \(\Delta H^{\circ}\) for the thermal decomposition of silver nitrate according to the following equation is +78.67 kJ:
\(\mathrm{AgNO}_{3}(s) \rightarrow A g N \mathrm{NO}_{2}(s)+\frac{1}{2} \mathrm{O}_{2}(g)\)
The standard enthalpy of formation of \(\mathrm{AgNO}_{3}(\mathrm{s})\) is -123.02 kJ/mol. Calculate the standard enthalpy of formation of \(\mathrm{AgNO}_{2}(s)\).
ANSWER:Step 1 of 2
Here, we are going to calculate the standard enthalpy of formation of .
Given that,