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A chemist mixes two liquids A and B to form a homoseneous
Chapter 1, Problem 102P(choose chapter or problem)
A chemist mixes two liquids \(A\) and \(B\) to form a homogeneous mixture. The densities of the liquids are 2.0514 g/mL for \(A\) and 2.6678 g/mL for \(B\). When she drops a small object into the mixture, she finds that the object becomes suspended in the liquid; that is, it neither sinks nor floats. If the mixture is made of 41.37 percent \(A\) and 58.63 percent \(B\) by volume, what is the density of the metal? Can this procedure be used in general to determine the densities of solids? What assumptions must be made in applying this method?
Questions & Answers
QUESTION:
A chemist mixes two liquids \(A\) and \(B\) to form a homogeneous mixture. The densities of the liquids are 2.0514 g/mL for \(A\) and 2.6678 g/mL for \(B\). When she drops a small object into the mixture, she finds that the object becomes suspended in the liquid; that is, it neither sinks nor floats. If the mixture is made of 41.37 percent \(A\) and 58.63 percent \(B\) by volume, what is the density of the metal? Can this procedure be used in general to determine the densities of solids? What assumptions must be made in applying this method?
ANSWER:
Step 1 of 3
The goal of the problem is to find the density of the metal and state if this procedure can be used in general to determine the densities of solids and also state the assumptions that must be made in applying this method.
Given:
The density of liquid A = 2.0514 g/mL.
The density of liquid A = 2.6678 g/mL.
Volume of A in mixture = 41.37 percent.
Volume of A in mixture = 58.63 percent.
The density of the metal =?