Solution Found!
What is for the formation of 1 mole of CO at I atm and
Chapter 6, Problem 4PE(choose chapter or problem)
What is \(\Delta U\) for the formation of 1 mole of CO at 1 atm and \(25^{\circ} \mathrm{C}\)?
\(C(\text { graphite })+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}(\mathrm{g})\)
\(\Delta H=-110.5\ \mathrm{kJ}/\mathrm{mol}\)
Questions & Answers
QUESTION:
What is \(\Delta U\) for the formation of 1 mole of CO at 1 atm and \(25^{\circ} \mathrm{C}\)?
\(C(\text { graphite })+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}(\mathrm{g})\)
\(\Delta H=-110.5\ \mathrm{kJ}/\mathrm{mol}\)
ANSWER:Step 1 of 3
The goal of the problem is to calculate for the formation of 1 mole of CO at 1 atm and 25°C.
Given reaction:
= - 110.5 KJ/mol
is the change in internal energy. In this case, it is calculated using the formula shown below:
Where = change in enthalpy
R = gas constant =
T = Temperature