Solution Found!
Calculate the standard enthalpy of formation of carbon
Chapter 6, Problem 9PE(choose chapter or problem)
Calculate the standard enthalphy of formation of carbon disulfide \(\left(C S_{2}\right)\) from its elements given that
\(C(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)\)
\(S(\text { rhombic })+\mathrm{O}_{2}(g) \rightarrow \mathrm{SO}_{2}(g)\)
\(\mathrm{CS}_{2}(l)+3 \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{SO}_{2}(g)\)
\(\Delta H_{r x n}^{\circ}=-393.5 \mathrm{~kJ} / \mathrm{mol}\)
\(\Delta H_{r x n}^{\circ}=-296.4 \mathrm{~kJ} / \mathrm{mol}\)
\(\Delta H_{r x n}^{\circ}=-1073.6 \mathrm{~kJ} / \mathrm{mol}\)
Questions & Answers
QUESTION:
Calculate the standard enthalphy of formation of carbon disulfide \(\left(C S_{2}\right)\) from its elements given that
\(C(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)\)
\(S(\text { rhombic })+\mathrm{O}_{2}(g) \rightarrow \mathrm{SO}_{2}(g)\)
\(\mathrm{CS}_{2}(l)+3 \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{SO}_{2}(g)\)
\(\Delta H_{r x n}^{\circ}=-393.5 \mathrm{~kJ} / \mathrm{mol}\)
\(\Delta H_{r x n}^{\circ}=-296.4 \mathrm{~kJ} / \mathrm{mol}\)
\(\Delta H_{r x n}^{\circ}=-1073.6 \mathrm{~kJ} / \mathrm{mol}\)
ANSWER:
Step 1 of 4
The desired reactant is 
Two moles of sulfur react with two moles of oxygen to form sulfur dioxide.
