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Consider these changes.Hg(l) ? Hg(g)302(g) ? 203(g)CuSO4 •

Chapter 6, Problem 14P

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QUESTION:

Consider these changes.

(a) \(\mathrm{Hg}(l) \longrightarrow \mathrm{Hg}(g)\)

(b) \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{O}_{3}(g)\)

(c) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(s) \longrightarrow \mathrm{CuSO}_{4}(s)+5 \mathrm{H}_{2} \mathrm{O}(g)\)

(d) \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{HF}(g)\)

At constant pressure, in which of the reactions is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done?

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QUESTION:

Consider these changes.

(a) \(\mathrm{Hg}(l) \longrightarrow \mathrm{Hg}(g)\)

(b) \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{O}_{3}(g)\)

(c) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(s) \longrightarrow \mathrm{CuSO}_{4}(s)+5 \mathrm{H}_{2} \mathrm{O}(g)\)

(d) \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{HF}(g)\)

At constant pressure, in which of the reactions is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done?

ANSWER:

Step 1 of 4

Part A.

Here, the reactants are in liquid state and the products are in gaseous state. This causes an increase in the level of mercury and makes W negative. Hence, in the given equation, the work is done by the system to the surroundings.

 

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