Solution Found!

Consider the reaction If 2.0 moles of H2O(g) are converted

Chapter 6, Problem 27P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Consider the reaction

\(\begin{aligned}2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow & 2\mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \\\Delta H &=483.6 \mathrm{~kJ} / \mathrm{mol}\end{aligned}\)

If \(2.0\) moles of \(\mathrm{H}_{2} \mathrm{O}(g)\) are converted to \(\mathrm{H}_{2}(g)\) and \(\mathrm{O}_{2}(g)\) against a pressure of \(1.0\) atm at \(125^{\circ} \mathrm{C}\), what is \(\Delta U\) for this reaction?

Questions & Answers

QUESTION:

Consider the reaction

\(\begin{aligned}2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow & 2\mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \\\Delta H &=483.6 \mathrm{~kJ} / \mathrm{mol}\end{aligned}\)

If \(2.0\) moles of \(\mathrm{H}_{2} \mathrm{O}(g)\) are converted to \(\mathrm{H}_{2}(g)\) and \(\mathrm{O}_{2}(g)\) against a pressure of \(1.0\) atm at \(125^{\circ} \mathrm{C}\), what is \(\Delta U\) for this reaction?

ANSWER:

Step 1 of 2

The goal of the problem is to calculate \(\Delta U\) for this reaction given.

Given reaction:

\(2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\)

Given:

\(\Delta H=483.6 \mathrm{~kJ} / \mathrm{mol}\)

Number of moles of \(\mathrm{H}_{2} \mathrm{O}=2.0 \text { moles }\)

Pressure (P) = 1.0 atm

Temperature (T) = \(125^{\circ} \mathrm{C}\)

\(\Delta U\) is calculated using the formula shown below:

\(\Delta U=\Delta H-R T \Delta n\)

where \(\Delta H\) = change in enthalpy.

R = gas constant = 8.314 J/mol?K

T = Temperature

n = number of moles

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back