Solution Found!
Answer: A sheet of gold weighing 10.0 g and at a
Chapter 6, Problem 35P(choose chapter or problem)
A sheet of gold weighing 10.0 g and at a temperature of \(18.0^{\circ} \mathrm{C}\) is placed flat on a sheet of iron weighing 20.0 g and at a temperature of \(55.6^{\circ} \mathrm{C}\). What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron. The specific heats of the metals are given in Table 6.2.)
Questions & Answers
QUESTION:
A sheet of gold weighing 10.0 g and at a temperature of \(18.0^{\circ} \mathrm{C}\) is placed flat on a sheet of iron weighing 20.0 g and at a temperature of \(55.6^{\circ} \mathrm{C}\). What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron. The specific heats of the metals are given in Table 6.2.)
ANSWER:Step 1 of 4
Heat energy can be calculated by the following formula;
...............................(1)
Here,
m = mass
s = Specific heat capacity
= Temperature difference.