Solution Found!
Answer: An ionic bond is formed between a cation A+ and an
Chapter 9, Problem 15P(choose chapter or problem)
An ionic bond is formed between a cation \(A^+\) and an anion \(B^-\). How would the energy of the ionic bond [see Equation (9.2)] be affected by the following changes? (a) doubling the radius of \(A^+\), (b) tripling the charge on \(A^+\), (c) doubling the charges on \(A^+\) and \(B^-\), (d) decreasing the radii of \(A^+\) and \(B^-\) to half their original values.
Questions & Answers
QUESTION:
An ionic bond is formed between a cation \(A^+\) and an anion \(B^-\). How would the energy of the ionic bond [see Equation (9.2)] be affected by the following changes? (a) doubling the radius of \(A^+\), (b) tripling the charge on \(A^+\), (c) doubling the charges on \(A^+\) and \(B^-\), (d) decreasing the radii of \(A^+\) and \(B^-\) to half their original values.
ANSWER:
Step 1 of 5
Here, we are going to find out the energy of the ionic bond at different changes of ions.
An ionic bond formed in between cation and
anion.
Lattice energy of a compound can be calculated by using Coulomb's law.
“This law states that potential energy (E) between two ions is directly proportional to the product of their charges and inversely proportional to the distance of separation between them.”
For a single ion and a single
ions are separated by distance r the potential energy of the ionic bond is given by
E
E = K
and
are the charges of the
and
ions.
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