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The species is the simplest polyatomic ion. The geometry
Chapter 9, Problem 135P(choose chapter or problem)
The species \(\mathrm {H}\) is the simplest polyatomic ion. The geometry of the ion is that of an equilateral triangle. (a) Draw three resonance structures to represent the ion. (b) Given the following information
\(2\mathrm{H}+\mathrm{H}^+\longrightarrow\mathrm{H}_3^+\quad\ \ \ \ \ \Delta H^{\circ}=-849\mathrm{\ kJ}/\mathrm{mol}\)
and \(\mathrm{H}_2\longrightarrow2\mathrm{H}\quad\ \ \ \ \ \Delta H^{\circ}=436.4\mathrm{\ kJ}/\mathrm{mol}\)
calculate \(\Delta H^{\circ}\) for the reaction
\(\mathrm{H}^{+}+\mathrm{H}_{2} \longrightarrow \mathrm{H}_{3}^{+}\)
Questions & Answers
QUESTION:
The species \(\mathrm {H}\) is the simplest polyatomic ion. The geometry of the ion is that of an equilateral triangle. (a) Draw three resonance structures to represent the ion. (b) Given the following information
\(2\mathrm{H}+\mathrm{H}^+\longrightarrow\mathrm{H}_3^+\quad\ \ \ \ \ \Delta H^{\circ}=-849\mathrm{\ kJ}/\mathrm{mol}\)
and \(\mathrm{H}_2\longrightarrow2\mathrm{H}\quad\ \ \ \ \ \Delta H^{\circ}=436.4\mathrm{\ kJ}/\mathrm{mol}\)
calculate \(\Delta H^{\circ}\) for the reaction
\(\mathrm{H}^{+}+\mathrm{H}_{2} \longrightarrow \mathrm{H}_{3}^{+}\)
ANSWER:Step 1 of 3
Resonance structures are sets of Lewis structures that explain how the electrons in a polyatomic ion or molecule become delocalized.