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The rate law for the reaction H2 + 2IBr ?12 + 2HBr is rate
Chapter 13, Problem 6RC(choose chapter or problem)
The rate law for the reaction \(\mathrm{H}_{2}+2 \mathrm{IBr} \rightarrow \mathrm{I}_{2}+2 \mathrm{HBr}\) is \(\text { rate }=k\left[\mathrm{H}_{2}\right][\mathrm{IBr}]\).Given that HI is an intermediate, write a two-step mechanism for the reaction.
Questions & Answers
QUESTION:
The rate law for the reaction \(\mathrm{H}_{2}+2 \mathrm{IBr} \rightarrow \mathrm{I}_{2}+2 \mathrm{HBr}\) is \(\text { rate }=k\left[\mathrm{H}_{2}\right][\mathrm{IBr}]\).Given that HI is an intermediate, write a two-step mechanism for the reaction.
ANSWER:Step 1 of 2
The rate of a reaction is defined as the rate at which the reaction proceeds. It can be expressed either as the rate of formation of the products or rate of disappearance of the reactants.
For example,
The rate of the reaction will be;
