Solution Found!
The reaction 2A?B is second order with a rare constant of
Chapter 13, Problem 7PE(choose chapter or problem)
The reaction 2A ⟶ B is second order with a rate constant of 51/M ᐧ min at 24°C. (a) Starting with \([A]_{0}\) = 0.0092 M, how long will it take for \([A]_{t}=3.7 \times 10^{-3}\) M? (b) Calculate the half-life of the reaction.
Questions & Answers
QUESTION:
The reaction 2A ⟶ B is second order with a rate constant of 51/M ᐧ min at 24°C. (a) Starting with \([A]_{0}\) = 0.0092 M, how long will it take for \([A]_{t}=3.7 \times 10^{-3}\) M? (b) Calculate the half-life of the reaction.
ANSWER:Step 1 of 4
Given data
Rate constant k=
Concentration of 
Concentration of 
The time taken by the reaction is calculated by using the integrated rate law for 
Where,
k is the rate constant of the second-order reaction.
t is the time taken by the reaction.
