Solution Found!
Given the same reactant concentrations, the reactionCO(g)
Chapter 13, Problem 38P(choose chapter or problem)
Given the same reactant concentrations, the reaction
\(\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \longrightarrow \mathrm{COCl}_2(\mathrm{~g})\)
at \(250^{\circ} \mathrm{C}\) is \(1.50 \times 10^3\) times as fast as the same reaction at \(150^{\circ} \mathrm{C}\). Calculate the activation energy for this reaction. Assume that the frequency factor is constant.
Questions & Answers
QUESTION:
Given the same reactant concentrations, the reaction
\(\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \longrightarrow \mathrm{COCl}_2(\mathrm{~g})\)
at \(250^{\circ} \mathrm{C}\) is \(1.50 \times 10^3\) times as fast as the same reaction at \(150^{\circ} \mathrm{C}\). Calculate the activation energy for this reaction. Assume that the frequency factor is constant.
ANSWER:Step 1 of 3
Given that the reaction is 
The Arrhenius equation can be written as follows.
Where k is the rate constant, A is the Arrhenius constant, E is the activation energy, R is the universal gas constant, T is the temperature.