Solution Found!
At 1280cCthe equilibrium constant (Kc) for the reaction is
Chapter 14, Problem 10PE(choose chapter or problem)
At \(1280^{\circ} \mathrm{C}\) the equilibrium constant \(\left(K_{c}\right)\) for the reaction
\(B r_{2}(g)\ \leftrightharpoons\ 2 B r(g)\)
is \(1.1 \times 10^{-3}\). If the initial concentrations are \(\left[B r_{2}\right]=6.3 \times 10^{-2}\ M\) and \([B r]=1.2 \times 10^{-2}\ M\), calculate the concentrations of these species at equilibrium.
Questions & Answers
QUESTION:
At \(1280^{\circ} \mathrm{C}\) the equilibrium constant \(\left(K_{c}\right)\) for the reaction
\(B r_{2}(g)\ \leftrightharpoons\ 2 B r(g)\)
is \(1.1 \times 10^{-3}\). If the initial concentrations are \(\left[B r_{2}\right]=6.3 \times 10^{-2}\ M\) and \([B r]=1.2 \times 10^{-2}\ M\), calculate the concentrations of these species at equilibrium.
ANSWER:Step 1 of 4
The given reaction is as follows;
