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A pressure difference of 6.00 X 104 Pa is required to

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 48E Chapter 12

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 48E

A pressure difference of 6.00 X 104 Pa is required to maintain a volume flow rate of 0.800 m3/s for a viscous fluid flowing through a section of cylindrical pipe that has radius 0.210 m. What pressure difference is required to maintain the same volume flow rate if the radius of the pipe is decreased to 0.0700 m?

Step-by-Step Solution:

Solution 48E Step 1: dV 3 Volume flow rate dt = 0.8 m /s Pressure difference p = 6.00 x 10 Pa 1 Radius of cylindrical pipe R = 0110 m Radius of cylindrical pipe after changing radius R = 0.070 m 2 Step 2: Since the fluid is viscous the pressure changes as the radius of the tube changes. The relationship between the change in pressure and the radius of the cylindrical tube is given by p L (assume that the length of the pipe is same) R 4

Step 3 of 4

Chapter 12, Problem 48E is Solved
Step 4 of 4

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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