In Example 22.6 the length of a 60 W, 240 ? lightbulb | StudySoup

Textbook Solutions for College Physics

Chapter 22 Problem 32P

Question

Problem 32P

In Example 22.6 the length of a 60 W, 240 Ω lightbulb filament was calculated to be 60 cm.

a. If the potential difference across the filament is 120 V, what is the strength of the electric field inside the filament?

b. Suppose the length of the bulb’s filament were doubled without changing its diameter or the potential difference across it. What would the electric field strength be in this case?

c. Remembering that the current in the filament is proportional to the electric field, what is the current in the filament following

the doubling of its length?

d. What is the resistance of the filament following the doubling of its length?

Reference: Example 22.6 :

Solution

Step 1 of 7)

The first step in solving 22 problem number trying to solve the problem we have to refer to the textbook question: Problem 32PIn Example 22.6 the length of a 60 W, 240 Ω lightbulb filament was calculated to be 60 cm.a. If the potential difference across the filament is 120 V, what is the strength of the electric field inside the filament?b. Suppose the length of the bulb’s filament were doubled without changing its diameter or the potential difference across it. What would the electric field strength be in this case?c. Remembering that the current in the filament is proportional to the electric field, what is the current in the filament followingthe doubling of its length?d. What is the resistance of the filament following the doubling of its length?Reference: Example 22.6 :
From the textbook chapter Current and Resistance you will find a few key concepts needed to solve this.

Step 2 of 7)

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full solution

Title College Physics 12 
Author Randall D. Knight
ISBN 9780321595492

In Example 22.6 the length of a 60 W, 240 ? lightbulb

Chapter 22 textbook questions

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